[BOJ] 10814 나이순 정렬 (JAVA)

https://www.acmicpc.net/problem/10814

10814번: 나이순 정렬

나이순으로 정렬하되, 나이가 같으면 입력받은 순서대로 출력하면 됩니다.

입력받은 순서를 기억하기 위해서 각 입력마다 index를 부여했습니다.

 

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.PriorityQueue;
import java.util.StringTokenizer;

public class Main {
	
    static BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    static StringBuilder sb = new StringBuilder();
    static StringTokenizer st;

    public static void main(String[] args) throws Exception {

        int N = Integer.parseInt(br.readLine());
        PriorityQueue<Member> pq = new PriorityQueue<>();
        for (int i = 0; i < N; i++) {
            st = new StringTokenizer(br.readLine(), " ");
            pq.offer(new Member(Integer.parseInt(st.nextToken()), st.nextToken(), i));
        }

        while(!pq.isEmpty()) {
            Member m = pq.poll();
            sb.append(m.age + " " + m.name + "\n");
        }
        System.out.print(sb.toString());

    }

    static class Member implements Comparable<Member> {

        int age, index;
        String name;

        public Member(int age, String name, int index) {
            this.age = age;
            this.name = name;
            this.index = index;
        }

        @Override
        public int compareTo(Member o) {
            if(this.age == o.age) return this.index - o.index;
            return this.age - o.age;
        }

    }

}